Projectile Motion: 3 methods to answer ALL questions!

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Summary

This video explains projectile motion by covering three main types of questions that appear in exams. It breaks down velocity into horizontal and vertical components, discusses how gravity affects each, and demonstrates problem-solving using suvat equations and basic speed-distance-time formulas.

Highlights

Introduction to Projectile Motion and its Components
00:00:00

The video introduces projectile motion, categorizing problems into three types: starting and ending at the same height, thrown straight, and starting/ending at different heights. It explains that a projectile's curved path is due to varying vertical velocity (affected by gravity) and constant horizontal velocity (unaffected by gravity). It then shows how to resolve a given velocity into its vertical (sin component) and horizontal (cos component) parts, emphasizing that the component closer to the angle uses cosine, but this can vary based on angle position.

Solving Complex Projectile Motion Problems (Type 1)
00:02:39

This section tackles a complex problem where a ball is thrown from a cliff. It explains the convention of using negative values for upward vertical velocity and positive for downward due to gravity. The four suvat formulas are introduced, highlighting that positive acceleration is used for downward motion. The video demonstrates how to find the maximum height (using vertical velocity and suvat), the vertical speed at landing, and the total velocity at landing by combining horizontal and vertical components using a right-angle triangle. It emphasizes keeping vertical and horizontal components separate but using total flight time for both.

Calculating Total Flight Time and Range
00:07:02

The video details how to calculate the total time of flight using vertical velocities and the v = u + at formula, stressing the importance of directional signs. It also shows how to find the range (horizontal distance) using the constant horizontal velocity and total flight time with the simple speed = distance/time formula. It reinforces that horizontal velocity is constant because gravity only acts vertically.

Solving Projectile Motion Problems (Type 2)
00:10:01

This part focuses on a scenario where a ball is thrown straight horizontally from a cliff. It clarifies that the initial vertical velocity is zero in this case. The video demonstrates finding the time of flight using the vertical distance and suvat equation, and calculating the final vertical velocity. It reiterates that horizontal velocity remains constant throughout the flight, as it's not affected by gravity.

Solving Projectile Motion Problems (Type 3)
00:12:12

The final problem type involves a ball thrown at an angle, where the goal is to find the maximum distance traveled and maximum height. It explains how to break the initial velocity into horizontal and vertical components. To find the horizontal distance, the time of flight is necessary, which is calculated using vertical components. For projectiles landing at the same height they started, the time to reach maximum height is half the total flight time. Using this, the total flight time is calculated, and then used with horizontal velocity to find the maximum horizontal distance (range).

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