Percent Compositions of Compound| Grade 9 Science Quarter 2 Week 8 | DepEd MELC-based

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Summary

This video explains how to calculate the percent composition of compounds using chemical formulas. It uses examples like an exam score, instant coffee ingredients, and ethanol to illustrate the concept and provide a step-by-step guide for calculation.

Highlights

Introduction to Percent Composition
00:00:00

The video introduces the topic of percent composition of compounds, which is the final lesson for Quarter 2 Week 8. The learning objective is to determine the percentage composition of a compound given its chemical formula and vice versa. An analogy with an exam score (85% correct answers) is used to explain the concept of percentage.

Practical Example: Instant Coffee
00:01:05

To further illustrate, the video uses the example of a 3-in-1 instant coffee sachet containing 10 grams of coffee, 13 grams of sugar, and 12 grams of milk, totaling 35 grams. It then demonstrates how to calculate the percentage composition of each ingredient: Coffee (28.57%), Sugar (37.14%), and Milk (34.29%). The sum of these percentages equals 100%.

Formula for Mass Percent
00:02:57

The importance of knowing how to calculate percent compositions in a laboratory setting for preparing solutions or verifying substance purity is highlighted. The formula for mass percent is introduced: Mass percent = (Mass of element / Mass of compound) * 100%.

Example: Ethanol (C2H6O)
00:03:27

The video then applies the formula to ethanol (C2H6O), an alcohol used in gasoline. It breaks down the composition: one mole of ethanol consists of two moles of carbon, six moles of hydrogen, and one mole of oxygen. The first step in calculating the percent composition is to determine the molar mass of ethanol.

Calculating Molar Mass of Ethanol
00:04:14

The molar mass of ethanol is calculated by finding the atomic mass of each element from the periodic table and multiplying by the number of atoms present: Carbon (12.01 g/mol * 2 = 24.02 g/mol), Hydrogen (1.008 g/mol * 6 = 6.048 g/mol), and Oxygen (16.0 g/mol * 1 = 16.0 g/mol). Summing these gives the molar mass of ethanol as 46.068 g/mol, rounded to 46.07 g/mol.

Calculating Mass Percent of Each Element in Ethanol
00:05:39

The video proceeds to calculate the mass percent of each element in ethanol. For Carbon: (24.02 g / 46.07 g) * 100% = 52.14%. For Hydrogen: (6.048 g / 46.07 g) * 100% = 13.14%. For Oxygen: (16.0 g / 46.07 g) * 100% = 34.73%.

Verification and Summary
00:07:29

A reminder is given that the sum of all mass percentages in a compound should ideally add up to 100%, and this serves as a good check for calculations. The lesson concludes by summarizing that percent composition is used to find the percentage of elements in a compound, requiring knowledge of molar mass, and is important in chemistry for analysis and determining empirical formulas.

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