SOLVING 1 VARIABLE IN TERMS OF THE OTHER (4th) FOURTH QUARTER GRADE 7 MATATAG TAGALOG MATH TUTORIAL

The lesson introduces the objective of solving one variable in terms of others within a formula, starting with a real-life application problem involving distance, speed, and time. The presenter asks how to find time if only distance and speed are given, setting the stage for rearranging formulas.

The video defines 'literal equations' as equations containing two or more variables. Examples of common literal equations from math and science are provided, such as the area of a triangle, volume of a rectangular prism, perimeter of a rectangle, and simple interest formula.

The first example demonstrates how to solve for time (t) in the distance formula (d = r * t). Using the division property of equality, both sides are divided by 'r' to isolate 't', resulting in the formula t = d / r.

The second example shows how to solve for height (h) in the volume formula (V = l * w * h). By dividing both sides by 'l' and 'w', the variable 'h' is isolated, leading to the formula h = V / (l * w).

This example tackles solving for height (h) in the area of a triangle formula (A = 1/2 * b * h). The multiplication property of equality is used to eliminate the fraction (multiplying by 2), and then the division property of equality is applied to isolate 'h', resulting in h = 2A / b.

The final example demonstrates solving for length (l) in the perimeter of a rectangle formula (P = 2l + 2w). The subtraction property of equality is used to move '2w' to the other side, and then the division property of equality is used to isolate 'l'. The solution can be further simplified to l = P/2 - w.

A practice activity with four items is provided for viewers to apply what they've learned. The solution to the initial real-life problem about the car's travel time is then presented, using the derived formula t = d / r to get an answer of 3 hours.