3-Reservoir Problem | Sample Problem

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Summary

This video provides a detailed solution to a 3-reservoir problem, focusing on determining the flow in pipe 3 and the elevation of reservoir C. It explains how to calculate head loss and flow rates using the Darcy-Weisbach equation, converting pressure to pressure head, and applying the concept of energy levels in fluid flow.

Highlights

Introduction to the 3-Reservoir Problem
00:00:06

The video introduces a sample problem involving three reservoirs and multiple pipes, emphasizing that this topic can be confusing in hydraulics. The goal is to determine the flow in pipe 3 and the elevation of reservoir C, using provided tabulated data for pipe lengths, diameters, and friction factors. The Darcy-Weisbach equation will be used for calculations.

Converting Pressure to Pressure Head
00:01:51

The video explains how to convert the given pressure at Junction J (4900 kPa) into pressure head (linear meters). This is done by dividing the pressure by the unit weight of water, resulting in 499.49 meters. This conversion is crucial for consistent units in energy calculations.

Calculating Energy at Junction J
00:03:05

The energy at Junction J is determined by adding the elevation of the junction (360 m) to the calculated pressure head (499.49 m), resulting in an energy level of 859.49 meters. This energy level is then used to deduce the direction of flow in the pipes.

Determining Flow Direction and Head Loss in Pipe 1
00:04:40

By comparing the energy at Reservoir A (930 m) and Junction J (859.49 m), it's established that flow from Reservoir A goes towards Junction J because 859.49 is less than 930. The head loss (hf1) for pipe 1 is calculated as the difference between these energy levels, which is 70.51 meters. The flow rate (Q1) in pipe 1 is then calculated using the Darcy-Weisbach equation, yielding 1.51 cubic meters per second.

Determining Flow Direction and Head Loss in Pipe 2
00:09:30

The video then determines the flow direction for pipe 2 by comparing the energy at Junction J (859.49 m) with Reservoir B (850 m). Since 859.49 is greater than 850, flow is from Junction J to Reservoir B. The head loss (hf2) for pipe 2 is 9.49 meters. The flow rate (Q2) in pipe 2 is calculated as 0.22 cubic meters per second.

Calculating Flow in Pipe 3 and Reservoir C Elevation
00:10:33

Recognizing that Q1 (1.51 m³/s) is greater than Q2 (0.22 m³/s), the remaining flow must go into pipe 3. Therefore, Q3 = Q1 - Q2, which is 1.29 cubic meters per second. Using this flow rate and the pipe 3 details, the head loss (hf3) for pipe 3 is calculated as 79.94 meters. Finally, the elevation of Reservoir C is determined by subtracting the head loss in pipe 3 from the energy at Junction J, resulting in an elevation of 780.09 meters.

Conclusion: Importance of Energy Levels
00:13:30

The video concludes by reiterating that the concept of fluid flow relies on the principle of higher energy moving towards lower energy. The key is to analyze energy levels rather than just elevations to correctly determine flow directions and head losses.

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